| In this case, F is proportional to f(x), so
that F1 corresponds to f(0) and
F2 to f(w*(1+Mph)), assuming that the
slits are resolved. |
| The image contrast cannot be determined without knowing the
proportionality constant between F and OD of the
film. |
| It can be shown that the three equal max. values on film occur at x=0,
±2w*(1+Mph) and the two equal min.
values at x=±w*(1+Mph), assuming the slits are resolved. |
| If the slits are not resolved the film profile will appear as two peaks
(or even one) instead of the expected three. |
| The slit pitch equals 1/(2*w) and is usually expressed in line-pairs per
millimeter. |
| The radiographic magnification equals 1+m. |
| Since the source is a disk, the line spread function is a circular:
l(x)=sqrt(r^2-x^2) for |x|<r and 0 otherwise and r=D/2. |
| The edge spread function is the integral of the line spread function:
e(x)=x*sqrt(r^2-x^2)+r^2*arcsin(x/r)+r^2*pi/2. |
| The resultant on the film plane is f(x)=e((w/2)*(1+m)-x)
-e((-w/2)*(1+m)-x) +e((3w/2)*(1+m)-x) -e((5w/2)*(1+m)-x) +e((-3w/2)*(1+m)-x)
-e((-5w/2)*(1+m)-x). |